Hi, there-- The Problem: The sum of three consecutive even numbers is 36. Find the numbers. Solution: A sum of consecutive even numbers is series like 2+4+6 or 8+10+12. Let x be the first even number in the series. Then the second even number is two more, or x+2. The third even number is two more than the second, x+2+2 or x+4. We know that the sum of the three numbers is 36. In algebra, we represent this relationship as x + x+2 + x+4 = 36 Now we solve this equation for x. First combine like terms. x+x+x is 3x and 2+4 is 6. 3x+6=36 Subtract 6 from both sides of the equation. 3x+6-6=36-6 3x=30 Divide both sides of the equation by 3. 3x/3 is x and 30/3 is 10. x=10 In the context of this problem, x=10 means that the first even number in the series is 10. The next two even numbers are 10+2=12 and 10+4=14. We need to check that 10,12, and 14 add up to 36. 10+12+14=36 True! That's it! Please email me if you have questions or comments about the solution. I'm happy to explain further and I'd appreciate the feedback. Ms.Figgy math.in.the.vortex@gmail.com