SOLUTION: in three days, Carter drove 2196 miles in 36 hours behind the wheel. tt day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the thi

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Question 623761: in three days, Carter drove 2196 miles in 36 hours behind the wheel. tt day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the third day than the first day, then how many hours did he drive each day ?
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

in three days, Carter drove 2196 miles in 36 hours behind the wheel. tt day he averaged 64 mph, the second day 62 mph, and the third day 58 mph. If he drove 4 more hours on the third day than the first day, then how many hours did he drive each day ?

Let time he drove on 1st day be T
Then time he drove on 3rd day = T + 4
Time he drove on 2nd day = 36 – (T + T + 4), or 36 – 2T – 4, or 32 – 2T

Distance on 1st day, plus distance on 2nd day, plus distance on 3rd day = total distance,
OR

64(T) + 62(32 – 2T) + 58(T + 4) = 2,196
64T + 1,984 – 124T + 58T + 232 = 2,196
64T – 124T + 58T = 2,196 – 1,984 – 232
– 2T = - 20
T, or time he drove on 1st day = , or hours

Time driven on 2nd day = 32 – 2T, or 32 – 2(10), or 32 – 20, or hours

Time driven on 3rd day = T + 4, or 10 + 4, or hours

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