SOLUTION: 6 times the sum of the digits of a two digit number is 1 less than the number obtained by reversing its digits. what is the product of its digits

Question 621231: 6 times the sum of the digits of a two digit number is 1 less than the number obtained by reversing its digits. what is the product of its digits
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let the two digits be a & b
then the number = 10a + b
:
Write what it says:
6 times the sum of the digits of a two digit number is 1 less than the number obtained by reversing its digits.
:
6(a+b) + 1 = 10b + a
6a + 6b + 1 = 10b + a
6a - a = 10b - 6b - 1
5a = 4b - 1
Divide by 5
a = .8b - .2
Two integer solutions
a = 7, b = 9; the number = 79; the product 63
and
a = 3, b = 4; the number = 34; the product 12

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