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At 9 am a car leaves a city traveling west.
Assume you mean
An HOUR and half later a faster car leaves the same city traveling east.
At 2 pm the two cars are 410 miles apart.
If the slower car travels at 2/3 the speed of the faster car, what is the speed of the fast car
Let s = speed of the fast car
s = speed of the slower car
Find the travel time of the slower car: 9 am to 2 pm = 5 hrs
Find the travel time of the faster car: 5 - 1.5 = 3.5 hrs
WRite a distance equation; dist = speed * time
slow car dist + fast car dist = 410 miles
s * 5 + 3.5s = 410
s + 3.5s = 410
Multiply by 3
10s + 10.5s = 1230
20.5s = 1230
s = 60 mph is the fast car
*60 = 40 mph is the slow car