SOLUTION: Please help me solve this question 6f + 1 = 10

Algebra.Com
Question 619162: Please help me solve this question 6f + 1 = 10
Found 2 solutions by IFY, dragonwalker:
Answer by IFY(62)   (Show Source): You can put this solution on YOUR website!

6f = 10 -1
6f = 9

divide both sides by 6
f = 6 /9 or
f = 2/3
Answer by dragonwalker(73)   (Show Source): You can put this solution on YOUR website!
You must rearrange.
6f + 1 = 10
You want to solve for f so you need to have the f on one side and the regular numbers on the other.
This means that you would need to move the 1 over to the right side of the equal sign as so:
6f = 10 - 1
note when I moved the 1 to the other side I changed the sign before it to -
((Some teachers may want you to write an intermediate step:
6f + 1 - 1 = 10 - 1 i.e. taking away the 1 from each side in order to move it
which leads to the +1 and -1 on the left cancelling each other out, but I was never shown to do it that way.))
So you have 6f = 10 - 1
so 6f = 9
now you want to find f, so you have to change 6f to f and you do this by dividing 6f by 6, but to do this you want to keep each side of the equation equal so if you divide the 6f by 6 you also need to divide everything else by 6, in this case 9 so:

f = 1 1/2
( I assume you know how to simplify a fraction, in this case 9/6 became 1 1/2 or if you need the answer in decimals: 1.5
so f= 1.5 or 1 1/2 if in fractions.





RELATED QUESTIONS

Please help me solve ((( -2(f+3g)+5(6f-2g)... (answered by glabow)
please help me solve this question. xix EN,... (answered by Alan3354)
I need some help. Can someone help me, please? f+8/f-1 divided by... (answered by jim_thompson5910)
please help me solve this question... (answered by rchill)
please help me solve this question... (answered by checkley71)
Please help me solve this question. SOlve each equation. Chech for extraneous solutions. (answered by lwsshak3)
Please help me solve this... (answered by richwmiller)
please help me to solve this question: (answered by richwmiller)
Please help me solve this question, (answered by Alan3354)