SOLUTION: a rectangle is 2x feet long and x+5 feet widw. the area is 600 square feet. what are the dimensions of the rectangle
Algebra.Com
Question 614214: a rectangle is 2x feet long and x+5 feet widw. the area is 600 square feet. what are the dimensions of the rectangle
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
2x(x + 5) = 600
2x^2 + 10x = 600 ___ x^2 + 5x = 300 ___ x^2 + 5x - 300 = 0
factoring ___ (x + 20)(x - 15) = 0
x + 20 = 0 ___ x = -20 ___ negative value not realistic
x - 15 = 0 ___ x = 15
RELATED QUESTIONS
What are the dimensions of a rectangle whose area is x^2-2x-143 square... (answered by mananth)
What is the area of a rectangle that is 260 feet long and 5 feet... (answered by waynest)
The width of a rectangle is 18 feet less than the perimeter. the area of the rectangle is (answered by lynnlo)
The length of a rectangle is 2 feet more than the width. The area of the rectangle is 2... (answered by Alan3354,Theo,ikleyn)
The perimeter of a rectangle is 54 feet and its area is 180 square feet. What are the... (answered by edjones)
What are the dimensions of a rectangle whose area is x2 - 6x - 216 square feet? (answered by KMST)
the area of a rectangle is 2x^2 - 11x + 15 square feet. The length of the rectangle is 2x (answered by drk)
the area of a rectangle is 2x^2-11x+15 square feet. the length of the rectangle is 2x-5... (answered by MathLover1,ReadingBoosters)
the length of a rectangle is 3 feet more than twice the width. the area is 90 square... (answered by ReadingBoosters)