SOLUTION: the sum of a 2 digit number and number formed by reversing the digits is 88 if the digits differ by 2. find the no.

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Question 612620: the sum of a 2 digit number and number formed by reversing the digits is 88 if the digits differ by 2. find the no.
Found 2 solutions by richard1234, MathTherapy:
Answer by richard1234(7193)   (Show Source): You can put this solution on YOUR website!
Two ways to do it:

Let the number be 10a+b, where a and b are digits. The "reversed" number is 10b+a, and



Therefore 17,26,35,44,53,62,71 are the only possible integers. 35 and 53 are the only ones that differ by two, so the answer is {35,53}.

The other way to do it is let the number be 10a + (a+2); switching the digits gives 10(a+2) + a. Do the same method as shown above.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
the sum of a 2 digit number and number formed by reversing the digits is 88 if the digits differ by 2. find the no.

Let the tens digit be T, and the units digit, U
Then: 10T + U + 10U + T = 88

11T + 11U = 88
11(T + U) = 11(8)
T + U = 8
T = 8 - U
|T – U| = 2, since it’s not known which digit is larger

|8 – U – U| = 2 ----- Substituting 8 – U for T

|8 – 2U| = 2

8 – 2U = 2 OR 8 – 2U = - 2

– 2U = 2 – 8 OR – 2U = - 10

- 2U = - 6 OR U = - 10/- 2

U = OR U =

U, or units digit = 3 or 5

This means that the original number could be either or

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