SOLUTION: Two cyclists leave towns 90 miles apart at the same time, and travel towards each other. One cyclist travels 5 mi/h slower than the other. If they meet in 2 hours, what is the rate
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Question 604618: Two cyclists leave towns 90 miles apart at the same time, and travel towards each other. One cyclist travels 5 mi/h slower than the other. If they meet in 2 hours, what is the rate of each cyclist?
I'm having a hard time figuring out the proper formula for this problem. Thank you in advance for your help!
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Two cyclists leave towns 90 miles apart at the same time, and travel towards each other. One cyclist travels 5 mi/h slower than the other. If they meet in 2 hours, what is the rate of each cyclist?
**
let x=rate of speed of faster cyclist
let (x-5)=rate of speed of slower cyclist
distance=rate*travel time (2 hrs)
..
2x+2(x-5)=90
2x+2x-10=90
4x=100
x=25
x-5=20
ans:
rate of speed of faster cyclist=25 mph
rate of speed of slower cyclist=20 mph
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