SOLUTION: A person invested $17,000 for one year,part at 10%, part at 12%, part at 15%. The total annual income from these investments was $2,110. The amount of money invested at 12% was $1,
Algebra.Com
Question 602640: A person invested $17,000 for one year,part at 10%, part at 12%, part at 15%. The total annual income from these investments was $2,110. The amount of money invested at 12% was $1,000 less than the amount invested at 10% and 15% combined. Find the amount invested at each rate.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Solve the 3X3 system. Recommend the substitution method to eliminate y first. Then solve for z in terms of x and solve the rest by substitution as well.
John
My calculator said it, I believe it, that settles it
RELATED QUESTIONS
We are currently working with linear functions and there is a story problem I cannot seem (answered by stanbon)
A person invested $6,700 for one year, part at 8%, part at 10% and the remainder at 12%. (answered by stanbon)
4.4. A person invested 17,000 for one year, part at 10% part at 12%. The total annual... (answered by ankor@dixie-net.com)
A person invested $7800 for one year,part at 6%, part at 9%, and the remainder at 12%.The (answered by mananth)
A person invested 8100$ for 1 year, part at 8%, part at 11%, and the... (answered by ikleyn)
A person invested $8200 for 1 year, part at 8%, part at 9%,... (answered by ikleyn)
Question content area top
Part 1
A person invested $6900 for 1 year, part at... (answered by josgarithmetic,greenestamps)
A person ivested $6,700 for one year, part at 8%, part at 10%, and the remained at 12%.... (answered by greenestamps)
a person invested $8000 for 1 year, part at 8%, part at 11%, and the remainder at 12%.... (answered by Theo)
