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put this solution on YOUR website!Given P (t) = 368 * (1.02)^t
r = 10^m
1.02 = 10^m
Taking log on both sides, we get:
Log(1.02) = m log(10)
0.008600 = m (1)
A = 10^b
368 = 10^b
Taking log on both sides, we get:
Log(368) = b (log 10)
2.56584 = b
y = mx + b
y = 0.0086 x + 2.56584 --------- EQN(1)
Put x = 60 ( 1950 + 60 = 2010 ) in the above equation, we get
y = 0.0086 (60) + 2.56584 = 0.516 + 2.56584 = 3.08184
y ≈ 3. 1 million
b. Use the function to determine the year during which the population of India will reach 2 billion.
Solution: Consider the equation (1), we get:
y = 0.0086 x + 2.56584
When y =2 billion,
2 = 0.0086 x + 2.56584
-0.56584 / 0.0086 = x
-65.795 = x
The year when the population will be 2 million is
1950 - 65.79 = 1885
