SOLUTION: Question--Leo Held a Garage Sale. He Priced All The Item For Either a Dime or a Quarter. His Sales Totaled Less Than $5.00. okay so thats the question i already have what the line

Question 592957: Question--Leo Held a Garage Sale. He Priced All The Item For Either a Dime or a Quarter. His Sales Totaled Less Than $5.00.
okay so thats the question i already have what the linear equation is but then it asks whats the maximum number of items that he could have sold for a quarter. I really need help I've been on this problem for a while. Thank you. Also if there is something I could Explain a little better please tell me. This is my first time on here.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
He Priced All The Item For Either a Dime or a Quarter.
His Sales Totaled Less Than $5.00.
:
Let d = no. of items sold for a dime
Let q = no. of items sold for a quarter
:
.10d + .25q = 5.00
:
What's the maximum number of items that he could have sold for a quarter?"
Max sold for .25: 5.00/.25 = 20 items, nothing for a dime
:
But assuming he sold some items for 10 cents, total$ has to be a multiple of .10, could not be 19 quarters (4.75)
.10d + .25(18) = 5.00
.10d + 4.50 = 5.00
.10d = 5.00 - 4.50
.10d = .50
d = 5 items for a dime, 18 for a quarter
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