SOLUTION: find the angles of a triangle if the second angle is 32 less than three times the first angle and third angle is 28 less than twice the first angle

Question 586272: find the angles of a triangle if the second angle is 32 less than three times the first angle and third angle is 28 less than twice the first angle
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the angles of a triangle if the second angle is 32 less than three times the first angle and third angle is 28 less than twice the first angle
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Let the 1st be "x"
Then the 2nd is "3x-32"
And the 3rd is "2x-28"
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Equation:
x + 3x-32 + 2x-28 = 180
6x - 60 = 180
6x = 240
x = 40 degrees (1st)
3x-32 = 120-32 = 88 degrees (2nd)
2x-28 = 80-28 = 52 degrees (3rd)
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Cheers,
Stan H.
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