You can
put this solution on YOUR website!A group of 60 people attend a ball game. There were twice as many children as adults in the group. Write a system of equations that you could use to set up this problem, where "a" is the number of adults and "c" is the number of children in the group. Solve the system of equations for "c", the number of children in the group.
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Equations:
a + c = 60
c = 2a
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Substitute for "c" and solve for "a":
a + 2a = 60
3a = 60
a = 20 (# of adults)
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Solve for "c":
c = 2a
c = 2*20 = 40 (# of children)
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cheers,
Stan H.
You can
put this solution on YOUR website!Let a = number of adults, and c = number of children
"A group of 60 people attend a ball game" means that a + c = 60.
"There were twice as many children as adults in the group" means that c = 2a
So the system of equations is
a + c = 60
c = 2a
Now let's solve for c
a + c = 60
a + 2a = 60
3a = 60
a = 60/3
a = 20
So there are 20 adults
c = 2a
c = 2(20)
c = 40
and there are
40 children
Note: add up the two counts to get 40+20 = 60, so this checks the first condition (that there are 60 people). Also, notice how 40 kids is exactly double 20 adults.