SOLUTION: A rectangular painting with a width of x centimeters has an area of x^2+50x square centimeters. Find a binomial that represents the length. I don't know where to begin here! I unde

Question 57965: A rectangular painting with a width of x centimeters has an area of x^2+50x square centimeters. Find a binomial that represents the length. I don't know where to begin here! I understand that the area (a) = x^2+50x, and that for solving for length and width for a rectangle we use a = l + w. From there, I am lost.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A rectangular painting with a width of x centimeters has an area of x^2+50x square centimeters. Find a binomial that represents the length.
:
We know area = L*W: x^2 + 50x = the area. and tells us the width = x. Find
length by dividing (x^2 + 50x) by the width which is given as x
:
= (x + 50) is the length

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