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Trains A and B are traveling in the same direction on parallel tracks.
Train A is traveling at 80 miles per hour and train B is traveling at 84 miles per hour.
Train A passes a station at 3:10 pm.
If train B passes the same station at 3:40 pm, at what time will train B catch up to train A?
From the given information, we know that Train B is .5 hrs behind A at at 3:10 pm
therefore Train B is:
.5 * 84 = 42 miles behind Train A at that time.
Let t = time required for Train B to catch Train A
Write a distance equation; dist = speed * time
Train B dist = Train A dist + 42 mi
84t = 80t + 42
84t - 80t = 42
4t = 42
t = 10.5 hrs for B to catch A
Convert 10.5 hrs to 10 hrs 30 min
Find the time from 3:10 pm: + 10:30 = 13:40 which is: