SOLUTION: Use Descartes' Rule of Signs to state the number of possible positive and negative real zeros of P(X) = 5X^4 + 21X^3 + 18X^2 - 6X

SOLUTION: Use Descartes' Rule of Signs to state the number of possible positive and negative real zeros of P(X) = 5X^4 + 21X^3 + 18X^2 - 6X - 4

Question 57444This question is from textbook Applied College Algebra
: Use Descartes' Rule of Signs to state the number of possible positive and negative real zeros of P(X) = 5X^4 + 21X^3 + 18X^2 - 6X - 4 This question is from textbook Applied College Algebra

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Use Descartes' Rule of Signs to state the number of possible positive and negative real zeros of
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P(X) = 5X^4 + 21X^3 + 18X^2 - 6X - 4
# of changes of sign is one
number of positive roots is one
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P(-x)=5x^4-21x^3+18x^2+6x-4
# of changes of sign is three
number of negative roots is 3
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Cheers,
Stan H.
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