SOLUTION: What is the equation of a circle having endpoints of it's diameter at (7,9)and (1,3)?

Question 562318: What is the equation of a circle having endpoints of it's diameter at (7,9)and (1,3)?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the equation of a circle having endpoints of it's diameter at (7,9)and (1,3)?
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The center is the midpoint.
x = (7+1)/2 = 4
y = (9+3)/2 = 6
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The radius is sqrt[(9-3)^2+(7-1)^2] = sqrt[36+36] = 6sqrt(2)
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Equation:
(x-4)^2 + (y-6)^2 = (6sqrt(2))^2
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Cheers,
Stan H.
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