SOLUTION: A company has a vehicle parking area of 1200m^2 with space for x cars and y trucks. Each car requires 20m^2 of space and each truck 100m^2 of space. a)show that x + 5y is equal

Question 549747: A company has a vehicle parking area of 1200m^2 with space for x cars and y trucks. Each car requires 20m^2 of space and each truck 100m^2 of space.
a)show that x + 5y is equal or less than 60.
b) there must be space for at least
i) 40 vehicles
ii) 2 trucks
write down inequalities to show this information.
Thank you.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
cars take up of space (in )
trucks take up of space (in )
If cars and trucks will fit into

<--> dividing everything by 20.
At least 40 vehicles translates into
At least 2 trucks translates into
The inequalities asked for are
, and
EXTRA THOUGHTS
It's only logical to ask that too, but that will happen anyway, as a consequence of the other restrictions above.
The inequalities determine a feasibility region. The boundaries for that feasibility region are:
, , and .
Those boundaries can be graphed as:
The feasibility region is the tiny triangle between the 3 lines, sides included.
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