SOLUTION: Find the dimensions of a rectangle whose perimeter is 26 meters and whose area is 40 square meters.

SOLUTION: Find the dimensions of a rectangle whose perimeter is 26 meters and whose area is 40 square meters.

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Question 547673: Find the dimensions of a rectangle whose perimeter is 26 meters and whose area is 40 square meters.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
Area = 40
perimeter =26
L*W=40
L=40/w
Perimeter = 2(L+W)=26
substitute L
2(40/w + w)=26
2(40+w^2)/W=26
40+W^2=26*w/2
W^2+40=13W
W^2-13W+40=0
W^2-8W-5W+40=0
W(W-8)-5(W-8)=0
(W-8)(W+5)=0
so W=8m the positive value
length = 5 m
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