SOLUTION: Chemistry. E-Chem Testing has a solution that is 80% base and another that is 30% base. A technician needs 150 L of a solution that is 62% base. The 150 L will be prepared by mixin
Algebra.Com
Question 547085: Chemistry. E-Chem Testing has a solution that is 80% base and another that is 30% base. A technician needs 150 L of a solution that is 62% base. The 150 L will be prepared by mixing the two solutions on hand. How much of each should be used?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
Base I 80 ---------------- x L
Base II 30 ------ 150 - x L
Mixture 62.00% ---------------- 150
80x+30(150-x)=62*150
80x+4500-30x=9300
80x-30x =9300-4500
50x=4800
/ 50
x =96L 80.00% Base I
54L 30.00% Base II
m.ananth@hotmail.ca
RELATED QUESTIONS
E-Chem Testing has a solution that is 80% base and another that is 30% base. A technician (answered by rfer)
E-chem Testing has a solution that is 80% base and another that is 30% base. A... (answered by uma)
E chem testing has a solution that is 80% base and another that is 30% base. A technician (answered by josgarithmetic)
A laboratory technician needs to make a 135-liter batch of a 20% acid solution. How can... (answered by josmiceli)
a lab technician has one solution that is 60% chlorinated and another that is 40%... (answered by stanbon)
A lab technician has one solution that is 60% chlorinated and another that is 40%... (answered by jorel1380)
A chemist has one solution that is 80% acid and another solution that is 30% acid. How... (answered by stanbon,richwmiller)
A chemist has one solution that is 80% acid and another solution that is 30% acid. How... (answered by josmiceli)
A lab technician has one solution that is 80 percent chlorinated, and another that is 40... (answered by Alan3354,scott8148)