# SOLUTION: 70. Ziggy’s Famous Yogurt blends regular yogurt that is 3% fat with its no-fat yogurt to obtain low fat yogurt that is 1% fat. How many pounds of no-fat yogurt should be mixed to

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: 70. Ziggy’s Famous Yogurt blends regular yogurt that is 3% fat with its no-fat yogurt to obtain low fat yogurt that is 1% fat. How many pounds of no-fat yogurt should be mixed to       Log On

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 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 53895: 70. Ziggy’s Famous Yogurt blends regular yogurt that is 3% fat with its no-fat yogurt to obtain low fat yogurt that is 1% fat. How many pounds of no-fat yogurt should be mixed to obtain 60 pounds of low fat yogurt? Write a system of two equations in two unknowns for each problem Solve the systems by the method of your choice.Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!Ziggy's famous yogurt blends regular yogurt that is 3% fat with its no fat yogurt to obtain low fat yogurt that is 1% fat. How many pounds of regular and how many pounds of non-fat yogurt should be mixed to obtain 60 pounds of lowfat yogurt. PLEASE HELP ASAP. thank you THESE ARE MATERIAL BALANCE PROBLEMS.THE PRINCIPLE IS TO APPLY TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.. THIS PRINCIPLE CAN BE APPLIED TO TOTAL MIXTURE AS A WHOLE AS WELL AS INDIVIDUAL COMPONENTS OF THE MIXTURE.LET US SEE THE APPLICATION USING YOUR PROBLEM. HERE THE MIXTURE COMPRISES 2 INPUTS-REGULAR YOGURT (RY) & NO FAT YOGURT (NFY) AND ONE OUT PUT-LOW FAT YOGURT (LFY).THE COMPONENT OF IMPORTANCE IN THE MIXTURE IS FAT CONTENT.SO WE TAKE 2 BALANCES HERE ..ONE FOR THE TOTAL MIXTURE AND ANOTHER FOR COMPONENT OF FAT IN THE MIXTURE. I..TOTAL BALANCE... INPUTS 1.QTY.OF.RY=X POUNDS 2.QTY OF NFY=Y POUNDS OUT PUT 1.QTY.OF LFY=60 POUNDS SO APPLYING TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET X+Y=60.............................I II..COMPONENT BALANCE..HERE IT IS FAT . INPUTS 1.QTY.OF FAT IN RY=X*3/100=3X/100 POUNDS 2.QTY OF FAT IN NFY=Y*0/100=0 POUNDS OUT PUT 1.QTY.OF FAT IN LFY=60*1/100=60/100 POUNDS SO APPLYING TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET 3X/100 + 0=60/100.............................II 3X=60 X=20 POUNDS. OF REGULAR YOGURT Y=60-20=40 POUNDS OF NO FAT YOGURT.