SOLUTION: the sum of ages of husband and his wife is four times the sum of ages of their children.four years ago,the ratio of sum of their ages to the sum of ages of their children was 18:1.
Algebra.Com
Question 537055: the sum of ages of husband and his wife is four times the sum of ages of their children.four years ago,the ratio of sum of their ages to the sum of ages of their children was 18:1.two years hence the ratio will be 3:1.how many children do they have?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Let h = husbands present age
Let w = wife's present age,
Let c = sum of children' age at this time
:
"the sum of ages of husband and his wife is four times the sum of ages of their children."
h + w = 4c
:
let n = number of children
four years ago, the ratio of sum of their ages to the sum of ages of their children was 18:1.
= 18; (You subtract 4 for each person)
h+w-8 = 18(c-4n)
h+w-8 = 18c - 72n
h+w = 18c - 72n + 8
Replace h+w with 4c
4c = 18c - 72n + 8
4c - 18c = -72n + 8
-14c = -72n + 8
14c = 72n - 8; multiplied by -1
:
two years hence the ratio will be 3:1.
= 3
h + w + 4 = 3(c+2n)
h + w = 3c + 6n - 4
Replace h+w with 4c
4c = 3c + 6n - 4
4c - 3c = 6n - 4
c = 6n - 4
:
14c = 72n - 8
replace c with (6n-4)
14(6n-4) = 72n - 8
84n - 56 = 72n - 8
84n - 72n = -8 + 56
12n = 48
n = 48/12
n = 4 children
:
:
Check this: find c,
c = 6(4) -4
c = 20; the sum of the children's ages
then
4(20) = 80 the sum of the parents ages
:
Use these values in the last statement:
two years hence the ratio will be 3:1.
= = 3
RELATED QUESTIONS
The sum of the ages of husband & his wife is four times the sum of the agesof their... (answered by ankor@dixie-net.com,josmiceli)
THE SUM OF AGES OF HUSBAND AND HIS WIFE IS 4 TIMES THE SUM OF AGES OF THEIR CHILDREN.4... (answered by ankor@dixie-net.com)
The sum of the ages of a man and his wife is six times the sum of the ages of their... (answered by ankor@dixie-net.com)
the sum of the ages of a man and his wife is 6 times the sum of the ages of their... (answered by Theo)
sum of ages of man and wife is 6 times the sum of age of children 2 years ago sum was 10 (answered by krutarthas)
The sum of the parent's age is twice the sum of their children's ages. Five years ago,... (answered by mananth)
A man is four times older than his son but five years older than his wife. The sum of... (answered by Edwin McCravy,Shin123,ikleyn,josgarithmetic)
the ratio of the present ages of John and Jack 2:9. four years ago, the sum of their ages (answered by lwsshak3,MathTherapy)
The ratio of the present ages of Kwasi and Yaw is 2:9. Four years ago the sum of their... (answered by ikleyn)