SOLUTION: A retailer spent $48 to purchase a number of mugs. Two of them were broken in the store, but by selling each of the remaining mugs for $3 above the original cost per mug, she made

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Question 5300: A retailer spent $48 to purchase a number of mugs. Two of them were broken in the store, but by selling each of the remaining mugs for $3 above the original cost per mug, she made a total profit of $22.
If the price for n mugs is $48, how can I express the cost per mug?
The number of mugs that are available for sale?
Rewrite the equation from above in the standard form of a quadratic equation?

Answer by rapaljer(4671)   (Show Source): You can put this solution on YOUR website!
This is an interesting problem. Let's start by letting
n= number of mugs purchased by the retailer
n-2 = number of mugs sold (two were broken and not able to be sold!)
C = cost per mug paid by the retailer
C + 3 = retail selling price of the mugs (for which retailer gets a $3 profit)

To answer your other questions:
If the price for n mugs is $48, then the cost per mug is $.
The number of mugs available for sale = n-2.

The equation is based upon the revenue from the sale of the mugs:
"Selling price per mug TIMES number of mugs sold = Revenue = Cost + Profit"
where

Substitute for the C in this equation:


Find the Least Common Denominator for the binomial above:




Multiply both sides by the denominator "n":


Subtract 70n from each side of the equation to set it equal to zero:



Now this is a GREAT place to use Ichudov's new process for solving quadratic equations, but unfortunately I haven't learned it yet. Maybe the Maestro will step in and add his touch to this solution. Anyway, I DO know that this equation DOES factor, since if you calculate you get 1936 and . So, solve it however you can . . .

If you factor it, this comes out to




n cannot be a negative fraction, so
n= 12 mugs were purchased.
n-2 = 10 mugs were sold.
$4 = cost to buy each mug
Add a $3 profit to each mug = $7 for each of the 10 mugs that were sold.

Check:
12 mugs were purchased at $4 each for a total of $48.
10 mugs were sold at $7 each for a total of $70. That gives a profit of $22.

R^2 at SCC


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