# SOLUTION: A local hospital is holding a two day marathon walk to raise funds for a new research facility. The total distance of the marathon is 26.2 miles. On the first day, Martha starts wa

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 Click here to see ALL problems on Linear Equations And Systems Word Problems Question 522519: A local hospital is holding a two day marathon walk to raise funds for a new research facility. The total distance of the marathon is 26.2 miles. On the first day, Martha starts walking at 10:00 am. She walks 4 miles per hour. Carol starts two hours later than Martha but decides to run to catch up to Martha. Carol runs at a speed of 6 miles per hour. Carol wants to reduce the time she takes to catch up to Martha by 1 hour. How can she do this by changing her starting time? How can she do this by changing her speed?Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!Martha --speed = 4mph---10.00 am Carol----speed ---6mph---12.00 noon x/4-2=x/6 x/4-x/6=2 (6x-4x)/24=2 2x=48 x=24 distance where she catches up Carol distance =24 carol speed = 6 carol time = 4 hours reduce by 1 hour carol time will be 3 hours distance = 24miles speed = 24/3 = 8 mph