SOLUTION: helllo, I need help with my project! I need to graph this equationThe admission fee at a small fair is $1.50 for children and $4.00 for adults. On a certain day 2,200 people ent

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Question 508801: helllo, I need help with my project!
I need to graph this equationThe admission fee at a small fair is $1.50 for children and $4.00 for adults. On a certain day 2,200 people enter the fair and $5050 is collected. How many children and how many adults attended? i am not sure how to do it at first i tried doing the box with the equation in the middle and then you give x like for example
x 4a+1.5c=5050 y
1 4(1)+1.5c=5050

can you help me solve this?
Thanks, Genesis






Found 2 solutions by Edwin McCravy, oberobic:
Answer by Edwin McCravy(20063)   (Show Source): You can put this solution on YOUR website!
There are two equation, (1) a PEOPLE equation and (2) a MONEY equation.
You have the MONEY equation correct:

 4a + 1.5c = 5050

But you are forgetting the PEOPLE equation which comes from:

 

or

a + c = 2200

So you have this system of equations:

 a +    c = 2200
4a + 1.5c = 5050

Solve that either by substitution or elimination and
you will get a = 700, c = 1500

Edwin
Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
a = number of adults
400a = sales of adult tickets in cents (I'm using cents to avoid the decimals later)
c = number of children
150c = sales of children's tickets in cents
.
a + c = 2200
so
a = 2200 -c
.
400a + 150c = 505000 cents
.
substitute
.
400(2200-c) + 150c = 505000
.
880000 -400c + 150c 505000
.
-250c = -375000
.
c = 1500
.
a = 2200-c
a = 700
.
check the receipts to see if this is correct
.
4*700 = 2800
1.50*1500 = 2250
2800 + 2250 = 5050
correct
.
Answer: They sold 700 adult and 1500 children tickets.
.
Done.
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