# SOLUTION: In addition to finding unions and intersections of intervals, it is possible to apply other operations to intervals. For instance, (-1,2)^2 is the interval that results from square

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 Question 50005This question is from textbook Applied College Algebra : In addition to finding unions and intersections of intervals, it is possible to apply other operations to intervals. For instance, (-1,2)^2 is the interval that results from squareing every number in the interval (-1,2). This gives [1,4). Thus (-1,2)^2 = [1,4). a. Find (-4,2)^2 b. Find 1/[-2,3], the reciprocal of every number in [-2,3]. c. Find ABS(-4,5), the absolute value of every number in (-4,5)This question is from textbook Applied College Algebra Answer by AnlytcPhil(1278)   (Show Source): You can put this solution on YOUR website!``` In addition to finding unions and intersections of intervals, it is possible to apply other operations to intervals. For instance, (-1,2)^2 is the interval that results from squareing every number in the interval (-1,2). This gives [1,4). Thus (-1,2)^2 = [1,4). Hey, that's wrong!!!!! It should be [0,4), That's because smallest number in (-1,2)² is 0² and the largest number is just less than but not including (2)² = 4. So that's the interval [0,4) a. Find (-4,2)^2 The smallest number is 0² and the largest number is just less than but not including (-4)² = 16 So that's the interval [0,16) -------------------------------- b. Find 1/[-2,3], the reciprocal of every number in [-2,3]. The smallest number is 1/(-2) = -1/2 and the largest number is 1/3. Both are included. However there is no number whose reciprocal is 0, so we must rule out 0. So that's the interval [-1/2, 0) U (0, 1/3] ------------------------------- c. Find ABS(-4,5), the absolute value of every number in (-4,5) The smallest number is ABS(0) = 0 and the largest number is just less than but not including ABS(5) = 5. So that's [0,5) Edwin```