SOLUTION: 20-foot piece of string is cut into two peices so that the longer piece is 5 feet longer than twice the shorter piece. find the lengths of both pieces.

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Question 499965: 20-foot piece of string is cut into two peices so that the longer piece is 5 feet longer than twice the shorter piece. find the lengths of both pieces.
Answer by oberobic(2304)   (Show Source): You can put this solution on YOUR website!
L = longer piece
S = shorter piece
L + S = 20 ft
so
L = 20 -S
.
L is 5 ft longer than twice the shorter.
L = 2S + 5
.
Equals are equal, so L = L
.
20-S = 2S + 5
Add S to both sides
20 = 3S +5
Subtract 5 from both sides
15 = 3S
so
3S = 15
Divide both sides by 3
S = 5
.
L+S = 20
L = 20 -S
L = 20 -5
L = 15.
.
Always check your work.
Is L 5 more than 2*S?
2*S = 10
2*S +5 = 15
L = 15
True.
.
Re-read the question to ensure you answer it.
The longer piece is 15 ft and the shorter piece is 5 ft.
.
Done.

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