SOLUTION: two cyclists start at the same point and travel in opposite directions. one cyclist travels8km/h faster than the other. if the two cyclists are 270km apart after 5 hours what is th

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Question 466675: two cyclists start at the same point and travel in opposite directions. one cyclist travels8km/h faster than the other. if the two cyclists are 270km apart after 5 hours what is the rate of each cyclist?
Found 2 solutions by rfer, solver91311:
Answer by rfer(16322)   (Show Source): You can put this solution on YOUR website!
x+x+8=270/5
2x+8=54
2x=54-8
2x=46
x=23 kph
x+8=31 kph
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


If they are traveling in opposite directions then their total speed is the sum of the two individual speeds. If they traveled a total of 270 klicks in 5 hours, then their total speed was 270 divided by 5 or 54 km/hr. Let represent the rate of the slower cyclist and then must be the faster one.



Solve for , then calculate

John

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