SOLUTION: The height of an object thrown upward from the floor of a canyon 106 ft. deep, with an initial velocity of 120 ft/sec is given by the equation:
h=-16t2 + 120t-106 How long will i
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Question 466060: The height of an object thrown upward from the floor of a canyon 106 ft. deep, with an initial velocity of 120 ft/sec is given by the equation:
h=-16t2 + 120t-106 How long will it take the object to rise to the height of the canyon wall? Round answer to the nearest hundreth.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The height of an object thrown upward from the floor of a canyon 106 ft. deep,
with an initial velocity of 120 ft/sec is given by the equation:
h=-16t2 + 120t-106 How long will it take the object to rise to the height of the canyon wall?
Round answer to the nearest hundreth.
:
Height of the canyon wall = 0, depth of the canyon -106, so we have
-16t^2 + 120t - 106 = 0
Use the quadratic formula:
In this equation: t=x, a=-16, b-120, c=-106
:
:
Two solutions
t =
t = 1.023 sec, this is the solution we want, time at the top of the wall on the way up
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