SOLUTION: find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second

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Question 46067: find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second

Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
first integer = i
second integer = i + 2
third integer = i + 4
i%28i+%2B+4%29+=+10%28i+%2B+2%29+%2B+71
i%5E2+%2B+4i+=+10i+%2B+91
i%5E2+-+6i+-+91+=+0
%28x+%2B+7%29%28x+-+13%29+=+0
x = -7 or x = 13
-7,-5,-3
or (you have two answers)
13,15,17