SOLUTION: FATHER'S AGE IS THRICE THE AGE OF HIS SON,FATHER'S AGE WAS 42 YRS.WHEN SON WAS BORN ,FIND THE FATHER'S AND SON'S AGE WHEN FATHER'S AGE WILL BE 7 TIMES OF THE SON'S AGE.

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Question 457255: FATHER'S AGE IS THRICE THE AGE OF HIS SON,FATHER'S AGE WAS 42 YRS.WHEN SON WAS BORN ,FIND THE FATHER'S AND SON'S AGE WHEN FATHER'S AGE WILL BE 7 TIMES OF THE SON'S AGE.
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
The key to this is that the difference in their
ages will always be the same
Let = Father's age now
Let = Son's age now
Let = years from now when Father's age
will be 7 times on's age
given:
(1)
(2)
The difference in their ages will still be
when
(3)
----------------------------------
Substitute (1) into (2)
(2) 3s - s = 42 }}}


and
(1)

and
(3)
(3)
(3)
(3)
(3)
and




When the Father was 49 and the Son was 7,
The Father's age was 7 times the Son's age


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