SOLUTION: for the first performance of a play in a community theater, 50 reserved-seat tickets and80 general-admission tickets were sold. the total reciepts were $980. for the second perfor
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Question 451979: for the first performance of a play in a community theater, 50 reserved-seat tickets and80 general-admission tickets were sold. the total reciepts were $980. for the second performance, 60 resevered-seat tickets and 90 general-admission tickets were sold. the total receipts were $1140. find the price of a resered-set ticket and the price of a general-admission ticket.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
for the first performance of a play in a community theater, 50 reserved-seat
tickets and80 general-admission tickets were sold.
the total reciepts were $980.
for the second performance, 60 resevered-seat tickets and 90 general-admission tickets were sold.
the total receipts were $1140.
find the price of a reserved-set ticket and the price of a general-admission ticket.
:
Let r = reserved seats price
Let g = general seats price
:
1st perform
50r + 80g = 980
Simplify, divide by 10
5r + 8g = 98
:
2nd perform
60r + 90g = 1140
Simplify, divide by 10
6r + 9g = 114
:
Multiply the 1st eq by 6, multiply the 2nd eq by -5, add the two equations
+30r + 48g = 588
-30r - 45g =-570
----------------------
0 + 3g = 18
g =
g = $6.00 general admission price
:
Find r using the 1st simplified equation
5r + 8(6) = 98
5r = 98 - 48
5r = 50
r =
r = $10 reserved ticket price
:
:
Check solution in the 2nd original equation
60r + 90g = 1140
60(10) + 90(6) = 1140
600 + 540 = 1140
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