Hi

Let x, y, z represent the numbers:

The sum of three numbers is 4:  x + y + x = 4

The first, minus the second, plus 4 times the third, is 11: x - y +4z = 11

The third plus 3 times the first, plus the second, is -6: 3x + y + z = -6

Solving for x by substitution

x + y + z = 4  OR (y + z) = (4 - x)

x - y +4z = 11

3x + y + z = -6 AND 3x + (4-x) = -6   x = -5 

Solving for z by Eliminating y

x + y + z = 4  

x - y +4z = 11

 2x + 5z = 15

 2*-5 + 5z = 15

         z = 5  and y = 4  (x+y+z = -5 + 5 + z = 4)

the Numbers are -5,4,5





 

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