SOLUTION: Hooke's Law states that the distance a spring stretches varies directly as the weight on the spring increases. A weight of 80 lbs. stretches a spring 4.5 inches. How far (to the

Question 43970: Hooke's Law states that the distance a spring stretches varies directly as the weight on the spring increases. A weight of 80 lbs. stretches a spring 4.5 inches. How far (to the nearest 0.01 inch) will a weight of 125 pounds stretch the spring?
Answer by adamchapman(301) (Show Source): You can put this solution on YOUR website!
The equation governing the extension of a spring is
where k is the stiffness (force per unit length) and F is the force applied. x is the extension of the spring.
A weight of 80 pounds stretches a spring 4.5 inches. So rearranging the equation given,

Now when 125 pounds are applied:
Rearranging:
the solution is x=7.03 inches (to the nearest 0.01 inch)
I hope this helps.
P.S. I am trying to start my own mathematics homework help website. I would be extremely grateful if you would send me your feedback on my help to adam.chapman@student.manchester.ac.uk.
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