SOLUTION: the length of a rectangle is 5 meters less than twice the width, if the area of the rectangle is 493 sq meters what are the demensions

Question 439283: the length of a rectangle is 5 meters less than twice the width, if the area of the rectangle is 493 sq meters what are the demensions
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
L=2W-5
LxW=Area
Wx(2W-5)=493
2W2-5W-493=0
(2W+29)(W-17)=0
W=-29/2 or 17
Throwing out the negative answer, we get length=29 m., width=17 m..

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=3969 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 17, -14.5. Here's your graph:

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