Hi

making 10 tons of concrete

Let x and (10-x) represent the amount of 65% and 17% cement mixtures respectively

Question states***Mixing to form 10 tons of 36.2% mixture

  .65x + .17(10-x) = .362*10

     .48x = .192*10

        x = .192*10/.48

        x = 4 tons of the 65% mixture needed



CHECKING our Answer***

.65*4  + .17*6 = 3.62

      

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
 Let  = tons of 17% mixture needed

Let  = tons of 65% mixture needed

given:

(1)  tons

(2) 

------------------------

(2) 

(2) 

Multiply both sides of (1) by 

and subtract (1) from (2)

------------------------

(2) 

(1) 





and, since

(1) 



6 tons of 17% mixture are needed

4 tons of 65% mixture are needed

check:

(2) 

(2) 





OK 

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