SOLUTION: Need help setting up this equation. If an object is projected vertically upward from an altitude of s0 feet with an initial velocity of v0 ft/sec, then its distance s(t) above the

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Need help setting up this equation. If an object is projected vertically upward from an altitude of s0 feet with an initial velocity of v0 ft/sec, then its distance s(t) above the       Log On


   



Question 434419: Need help setting up this equation. If an object is projected vertically upward from an altitude of s0 feet with an initial velocity of v0 ft/sec, then its distance s(t) above the ground after t seconds is
s(t) = −16t2 + v0t + s0.If s(1) = 79 and s(4) = 64, what are v0 and s0?

Found 2 solutions by solver91311, josmiceli:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!












Just solve the 2X2 system.

John

My calculator said it, I believe it, that settles it
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+s%28t%29+=+-16t%5E2+%2B+v%5B0%5D%2At+%2B+s%5B0%5D+
+s%5B1%5D+=+79+
+79+=+-16%2A%281%29%5E2+%2B+v%5B0%5D%2A1+%2B+s%5B0%5D+
+v%5B0%5D+%2B+s%5B0%5D+=+79+%2B+16+
(1) +v%5B0%5D+%2B+s%5B0%5D+=+95+
and
+s%284%29+=+64+
+64+=+-16%2A%284%29%5E2+%2B+v%5B0%5D%2A4+%2B+s%5B0%5D+
+4v%5B0%5D+%2B+s%5B0%5D+=+64+%2B+256+
(2) +4v%5B0%5D+%2B+s%5B0%5D+=+320+
Subtract (1) from (2)
(2) +4v%5B0%5D+%2B+s%5B0%5D+=+320+
(1) +-v%5B0%5D+-+s%5B0%5D+=+-95+
+3v%5B0%5D+=+225+
+v%5B0%5D+=+75+
and
(1) +75+%2B+s%5B0%5D+=+95+
+s%5B0%5D+=+20+
check answers
+64+=+-16%2A%284%29%5E2+%2B+v%5B0%5D%2A4+%2B+s%5B0%5D+
+64+=+-16%2A%284%29%5E2+%2B+75%2A4+%2B+20+
+64+=+-256+%2B+300+%2B+20+
+64+=+44+%2B+20+
+64+=+64+
OK