SOLUTION: 10) A plane flew 1000 miles with a tailwind in 2 hours. the return trip against the wind took 2 1/2 hours. Find the speed of the wind and the speed of the plane in still air.
I
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Question 42788This question is from textbook Intermediate Algebra
: 10) A plane flew 1000 miles with a tailwind in 2 hours. the return trip against the wind took 2 1/2 hours. Find the speed of the wind and the speed of the plane in still air.
I have the equations y-x(210)=1000 and x+y(150)=1000 is that correct and how will I solve.
12) Sue miller had to move some supplies. She rented a Portland Rent-A-Truck in April for 5 days and drove 150 miles. She paid $180 for the rental in April.In May she rented again for 7 days and drove 320 miles. She paid $274 for the rental in MAy. How much does Portland rent-a-truck charge daily and how much do they charge a mile?
This question is from textbook Intermediate Algebra
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
WIND SPEED =W
PLANE SPEED IN STILL AIR =P
SPEED IN TAIL WIND =P+W
.SPEED IN HEAD WIND =P-W
D=1000
TIME FOR TRAVEL IN TAIL WIND =1000/(P+W)=2
..OR
P+W=500
..I
TIME FOR TRAVEL IN HEAD WIND =1000/(P-W)=2.5
..OR
P-W=400
..II
EQN.I+EQN.II
.2P=900
..P=450
HENCE W =50
---------------------------------------
LET RENT/DAY=D
.AND
..RATE PER MILE =M
CHARGE FOR 5 DAYS =5D
.CHARGE OR 150 MILES =150M
.TOTAL = 5D+150M=180
.OR
.D+30M=36
.I
CHARGE FOR 7 DAYS =7D
.CHARGE OR 320 MILES =320M
.TOTAL = 7D+320M=274
..
.II
EQN.II-7*EQN.I
7D+320M-7D-210M=274-252=22
..110M=22
..M=0.2 $/MILE
D=36-30*0.2=36-6=30 $/DAY
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