SOLUTION: The sum of two numbers is 80 and the greatest number exceeds twice the smaller by 11. Find the numbers
Algebra.Com
Question 414350: The sum of two numbers is 80 and the greatest number exceeds twice the smaller by 11. Find the numbers
Answer by rfadrogane(214) (Show Source): You can put this solution on YOUR website!
The sum of two numbers is 80 and the greatest number exceeds twice the smaller by 11. Find the numbers.
Sol'n:
let: x -the larger number
y-the smaller number
x+y=80 ---(1)
x=2y+11 ---(2)
from (2):
x-2y=11
x+y=80
=======
-3y=-69
y=23
for x:
x=80-23=57
thus: x=57 & y=23 ---answer
^_^
RELATED QUESTIONS
The sum of two numbers is 80 and the greater number exceeds twice the smaller by 11. find (answered by KlambinRonsentaswer,Alan3354)
the sum of two numbers is 90 and the greater number exceeds twice the smaller by 15. find (answered by Alan3354)
sum of two numbers is 58. the greater number exceeds twice the smaller number by 1. find... (answered by TimothyLamb)
The sum of two numbers is90 and the greater number exceeds twice the smaller by 15.find... (answered by fractalier)
Find two numbers where three times the smaller number exceeds the larger by 5 and the sum (answered by addingup)
One number exceeds by 8, and the sum of the smaller and twice is 40. Find the product of... (answered by greenestamps)
The sum of two numbers is 17, and twice the larger exceeds three times the smaller by 4.... (answered by ikleyn)
The sum of two numbers is 43. Twice the larger number exceeds three times the smaller... (answered by eperette)
the sum of two numbers is 62, the greater number exceeds twice the smaller number by 5.... (answered by lynnlo)