SOLUTION: Would the set of ordered pairs (x,y) where x = the first name of people in this course and y = the birth dates of people in this course define a function? Why or why not

Algebra.Com
Question 412097: Would the set of ordered pairs (x,y) where x = the first name of people in this course
and y = the birth dates of people in this course define a function? Why or why not

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


Possibly. If no two people in the set of people who are in "this course" have the same first name, or for any group of people who are in "this course" that do have identical first names the group shares a common birthday, then the set of ordered pairs (x,y) where x = the first name of people in this course and y = the birth dates of people in this course does indeed define a function. However, if there is just one pair of people who have the same name but different birthdays, then this is not a function.

In order for a relation to be a function, the output must be unique for any given input.

John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism


RELATED QUESTIONS

the ordered pairs in the sets shown below are of the form (x,y) in which set of ordered... (answered by Edwin McCravy)
Express the set of ordered pairs for: a) {(x,y)! x=y^2} b) {(x,y); x=5} (answered by lynnlo)
Determine the ordered pairs for the give set of y-values -x - 4y = 2;... (answered by ewatrrr)
ordered pairs for the solution of x-y=4 (answered by stanbon)
what are the ordered pairs of x-y=1? (answered by stanbon)
If y varies directly as x, what is the value of y in these ordered pairs? (5,8) and... (answered by Alan3354)
ADDED ADDITIONAL EXPLANATION AND WORKING FOR THE SECOND PROBLEM..ONLY YOU NEED TO DO THE... (answered by venugopalramana)
here's my problem: tickets for the homecoming dance cost $20 for a single ticket or $35... (answered by glabow)
graph the following equation and name the x and y intercepts as ordered pairs 2x +y... (answered by Fombitz)