SOLUTION: An egg is dropped fron a height of 80 feet. Ignoring air resistance, the velocity of the egg increases at the rate of 32 feet per second each second it falls. The function h(v)=-

Question 408888: An egg is dropped fron a height of 80 feet. Ignoring air resistance, the velocity of the egg increases at the rate of 32 feet per second each second it falls. The function h(v)=-1/64v^2+80 can be used to find the height, h, of the egg in feet when it has reached a velocity of 'v' feet per second. What is the velocity of the eff to the nearest foot per second when it is 5 feet above the ground?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
simply subsitute 5 for h(v) and solve for v:
h(v)=-1/64v^2+80
5=-1/64v^2+80
-75=-1/64v^2
75=1/64v^2
75*64=v^2
4800 = v^2
69 feet per second = v

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