SOLUTION: A chemist has two solutions. one has 40% the other 25% concentrate. how many liters of each solution must be mixed to obtain 129liters of 34% solution?? I missed class yesterday

Question 403224: A chemist has two solutions. one has 40% the other 25% concentrate. how many liters of each solution must be mixed to obtain 129liters of 34% solution??
I missed class yesterday n today n this question is on my homework n i have no idea how i would set it up. plz help....
Found 2 solutions by josmiceli, lwsshak3:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Lt = liters of 40% solution needed
Let = liters of 25% solution needed
In words:
(total liters of concentrate)/(total liters of solution) = 34%
given:
(1)
(2)
-------------------------------
From (2):
(2)
Multiply both sides by
(2)
Multiply both sides of (1) by
and subtract from (2)
(2)
(1)

and, from (1),

77.4 liters of the 40% solution and 51.6 liters
of the 25% solution are needed
check answer:
(2)
(2)
You can do the math to check answer

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
A chemist has two solutions. one has 40% the other 25% concentrate. how many liters of each solution must be mixed to obtain 129liters of 34% solution??
I missed class yesterday n today n this question is on my homework n i have no idea how i would set it up. plz help....
..
let x=liters of 40% concentrate
then 129-x = liters of 25% concentrate
.4x+.25(129-x)=.34(129)
.4x+.25(129)-.25x=.34(129)
.15x=.34(129)-.25(129)
.15x=129(.34-.25)
x=129(.09)/.15
x=77.4 liters
129-x=129-77.4=51.6 liters
ans: 77.4 liters of the 40% concentrate and 51.6 liters of the 25% concentrate must be mixed to obtain 129 liters of 34% solution.
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