SOLUTION: Two fishermen go ice fishing one morning. By noon, Fisherman A has 6 fish and is catching 2 fish per hour. Fisherman B has 4 fish and is catching 3 per hour. Assume they will conti

Question 388639: Two fishermen go ice fishing one morning. By noon, Fisherman A has 6 fish and is catching 2 fish per hour. Fisherman B has 4 fish and is catching 3 per hour. Assume they will continue catching fish at the same rate.
Write a system of equations that relates the time to the total fish caught.
Found 2 solutions by richard1234, CharlesG2:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Let h be the number of hours past noon. Then A fishes 6 + 2h, while B fishes 4 + 3h. The total number of fish caught is (6 + 2h) + (4 + 3h) = 10 + 5h.
Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
Two fishermen go ice fishing one morning. By noon, Fisherman A has 6 fish and is catching 2 fish per hour. Fisherman B has 4 fish and is catching 3 per hour. Assume they will continue catching fish at the same rate.
Write a system of equations that relates the time to the total fish caught.

A = 6 + 2t
B = 4 + 3t
where t is time in hours, A is total for fisherman A,
B is total for fisherman B
total fish caught = A + B = 6 + 2t + 4 + 3t = 10 + 5t

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