SOLUTION: I need help with Linear Equation with two variables
A rectangular lot whose perimeter is 480 feet is fenced along three sides. An expensive fencing along the lotʹs
length
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Question 382260: I need help with Linear Equation with two variables
A rectangular lot whose perimeter is 480 feet is fenced along three sides. An expensive fencing along the lotʹs
length costs $16 per foot , and an inexpensive fencing along the two side widths costs only $9 per foot. The total
cost of the fencing along the three sides comes to $4040. What are the lotʹs dimensions?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A rectangular lot whose perimeter is 480 feet is fenced along three sides. An expensive fencing along the lotʹs length costs $16 per foot , and an inexpensive fencing along the two side widths costs only $9 per foot. The total
cost of the fencing along the three sides comes to $4040. What are the lotʹs dimensions?
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Let i be the inexpensive and e the expensive.
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Measure Equation: e + 2i = 480 ft.
Value Equation:: 16e + 9i = 4040
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Multiply thru the Measure Eq. by 16 to get:
16e + 32i = 16*480
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Subtract the Value Eq. from that and solve for "i":
23i = 3640
i = 158.26 ft (length of the inexpensive dimension)
----
Substitute into e + 2i = 480 to solve for "e":
e + 2*158.26 = 480
e = 163.48 ft (length of the expensive dimension)
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Cheers,
Stan H.
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