Hi,

Using the point-slope formula, to determine slope of L1

Points are (-4,0) and (0,6)which are the x and y intercepts 

  m = 6-0  / 0-(-4) = 6/4 = 3/2  

the standard slope-intercept form for an equation of a line is: y = mx + b  

where m is the slope and b the y-intercept.  Equation of L1 is y = (3/2)x + 6

Line2 parellel to L1 also has slope of 3/2

 y = 3/2x + b   L2 is to pass thru Pt(0,0) so b = 0

Equation of L2 is y = (3/2)x



 

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