SOLUTION: One number is 1 less than a second number. Twice the second number is 20 less than 4 times the first. Find the two numbers.
I have tried dividing 20 by 4 and adding 1 but that
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Question 377756: One number is 1 less than a second number. Twice the second number is 20 less than 4 times the first. Find the two numbers.
I have tried dividing 20 by 4 and adding 1 but that still does not work I know the answer is 11 and 12 but I would like to know how to figure it out on my own
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
let f=first and s=second
"One number is 1 less than a second number" ___ f = s - 1
"Twice the second number is 20 less than 4 times the first" ___ 2s = 4f - 20
substituting the value of f ___ 2s = 4(s - 1) - 20
2s = 4s - 4 - 20 ___ 24 = 2s ___ 12 = s
f = (12) - 1 = 11
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