SOLUTION: The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle.

Question 37660This question is from textbook
: The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle. This question is from textbook

Answer by mszlmb(115) (Show Source): You can put this solution on YOUR website!
Perimeter=length(2)+width(2)
1/4L=2W divide both sides by 2
1/8L=W, meaning the W:L ratio is 1:.125
sooo
2(X+.125X)=150 X is the width and .125X is the length..divide by 2
1.125X=75 becuz 1x+.125x=1.125x..divide by 1.125
x=66 2/3
The dennmitois are X and 1.125X, namely, 66.6667, and 7.5
Pesale Cechk it oevr to fnid if I am rihgt or wnorg

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