SOLUTION: The intensity I of a television signal varies inversely as the square of distance d from the transmitter. If the intensity is 25W/m^2 at a distance of 2 km, how far from the trans

Question 375493: The intensity I of a television signal varies inversely as the square of distance d from the transmitter. If the intensity is 25W/m^2 at a distance of 2 km, how far from the transmitter are you when the intensity is 2.6W/m^2?
Unfortunately, we did not go over this in class so I've been struggling with trying to figure it out. I want to think the formula to start with is I = k/d^2 after that I am stumped. I don't understand what 2.6W/m^2 represents.
Any help would greatly be appreciated.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You are off to a good start! You have written the inverse variation function for intensity (I):
Now you need to find the value of k, the constant of variation. You do this by substituting the given values of W/m^2 and meters:
so that...
Now the function for intensity looks like:
Now you can answer the question posed in the problem:
"How far (d) are you from the transmitter when the intensity (I) is 2.6W/?
Substitute the values into the last equation:
Solve for .
Take the square root of both sides.
meters.
meters.
Intensity is Watts per square meter or
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