SOLUTION: The sum of twice one number and 3 times another is 41. If the second is subtracted from the first, the difference is 8. What are the numbers?

Question 369560: The sum of twice one number and 3 times another is 41. If the second is subtracted from the first, the difference is 8. What are the numbers?
Answer by acalgebra(30) (Show Source): You can put this solution on YOUR website!
Let the first number be x and the second number be y, then:
and

The easiest way to solve this is to multiply the second equation by 3:

Now, add the equations:

Combine like terms:

Divide both sides by 5 to simplify:

Now, substitute 13 for each x in one of the original equations. In this case, the second equation will be easier.

Add y to each side:

Subtract 8 from each side:

So, and .
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