SOLUTION: The length of a rectangle is 9 feet more than its width. The perimeter is 58 feet. find the dimensions.(prior knowledge: perimeter=2 times the length plus 2 times the width) How do

Question 366912: The length of a rectangle is 9 feet more than its width. The perimeter is 58 feet. find the dimensions.(prior knowledge: perimeter=2 times the length plus 2 times the width) How do you write that?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!



Hi, 

Let x represent the width, then the length would be (x+9ft)

2(x+9ft) + 2*x = 58ft



Or

x = 10ft, the width.  the length = 19

2*10ft + 2*19ft = 20ft + 38ft = 58ft 

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